![Range of function $ \frac{1}{n\pi}(1-\cos(n\pi))\sin(\frac{n\pi}{2})$ and determination of Fourier coefficients - Signal Processing Stack Exchange Range of function $ \frac{1}{n\pi}(1-\cos(n\pi))\sin(\frac{n\pi}{2})$ and determination of Fourier coefficients - Signal Processing Stack Exchange](https://i.stack.imgur.com/zCB3W.png)
Range of function $ \frac{1}{n\pi}(1-\cos(n\pi))\sin(\frac{n\pi}{2})$ and determination of Fourier coefficients - Signal Processing Stack Exchange
Evaluate the following limit : lim(n→∞) n sin(π/4n) cos(π/4n) - Sarthaks eConnect | Largest Online Education Community
![calculus - Proving $\sum_{n=1}^{\infty }\frac{\cos(n)}{n^4}=\frac{\pi ^4}{90}-\frac{\pi ^2}{12}+\frac{\pi }{12}-\frac{1}{48}$ - Mathematics Stack Exchange calculus - Proving $\sum_{n=1}^{\infty }\frac{\cos(n)}{n^4}=\frac{\pi ^4}{90}-\frac{\pi ^2}{12}+\frac{\pi }{12}-\frac{1}{48}$ - Mathematics Stack Exchange](https://i.stack.imgur.com/ZUBlP.png)
calculus - Proving $\sum_{n=1}^{\infty }\frac{\cos(n)}{n^4}=\frac{\pi ^4}{90}-\frac{\pi ^2}{12}+\frac{\pi }{12}-\frac{1}{48}$ - Mathematics Stack Exchange
![sequences and series - Using roots of unity to prove that $\cos\frac{\pi }{2n}\cos\frac{2\pi}{2n}\cdots\cos\frac{(n-1)\pi}{2n}=\frac{\sqrt{n}}{2^{n-1}}$ - Mathematics Stack Exchange sequences and series - Using roots of unity to prove that $\cos\frac{\pi }{2n}\cos\frac{2\pi}{2n}\cdots\cos\frac{(n-1)\pi}{2n}=\frac{\sqrt{n}}{2^{n-1}}$ - Mathematics Stack Exchange](https://i.stack.imgur.com/plfM7.jpg)
sequences and series - Using roots of unity to prove that $\cos\frac{\pi }{2n}\cos\frac{2\pi}{2n}\cdots\cos\frac{(n-1)\pi}{2n}=\frac{\sqrt{n}}{2^{n-1}}$ - Mathematics Stack Exchange
![real analysis - How to prove that $\lim(\underset{k\rightarrow\infty}{\lim}(\cos(|n!\pi x|)^{2k}))=\chi_\mathbb{Q}$ - Mathematics Stack Exchange real analysis - How to prove that $\lim(\underset{k\rightarrow\infty}{\lim}(\cos(|n!\pi x|)^{2k}))=\chi_\mathbb{Q}$ - Mathematics Stack Exchange](https://i.stack.imgur.com/DDSHn.png)